Include correct answer in choices for G5608.
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The resulting capacitance for three capacitors in parallel will ALWAYS be less than the smallest of the three capacitor values. The answer for this question in 576.9 pF, NOT 576 nF given in the choices. Looks like a typo.
Not planned Suggested by: WiseInTexas • Upvoted: 12 Jan, '22 • Comments: 2
Richard Bateman Admin
We don’t write the questions, we just load them. If you believe the question is wrong please contact the NCVEC.
Also just for your information -- assuming you see this -- the correct answer to question G5C08 is not "576.9 pF" but actually "10.750 nanofarads" -- and I verified the math and it's correct.
Capacitors in parallel add, so the total capacitance is the *sum* of the three values. You're confusing series and parallel.